x^2-195x+7200=0

Solution for x^2-195x+7200=0 equation:

x^2-195x+7200=0

a = 1; b = -195; c = +7200;
Δ = b2-4ac
Δ = -1952-4·1·7200
Δ = 9225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9225}=\sqrt{225*41}=\sqrt{225}*\sqrt{41}=15\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-195)-15\sqrt{41}}{2*1}=\frac{195-15\sqrt{41}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-195)+15\sqrt{41}}{2*1}=\frac{195+15\sqrt{41}}{2}
$